World Languages, asked by dainvincible1, 1 year ago


A tank is filled in 5 hours by three pipes A, B and C. The pipe C is twice as fast as B and B is twice as fast as A. How much time will pipe A alone take to fill the tank?

Answers

Answered by wanderlust1301
2
5/7 hrs ie 5/7*60 minutes
Answered by SupermanINFINITY
0
♠Answer♠

Let The Time Taken By The Fastest tap i.e. C be 'x'

So , A + B + C = 5 hour

A + 2C + C = 5

4x + 2x + x = 5

7 x = 5

x = 5/7 Hr

And , As A takes 4x time ,

Time taken by A = 20/7 Hr

#SupermanINFINITY
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