A tank is filled in 5 hours by three pipes A, B and C. The pipe C is twice as fast as B and B is twice as fast as A. How much time will pipe A alone take to fill the tank?
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Let the time taken by pipe A alone to fill the tank be x hours.
Pipes B and C will take x/2 and x/4 hours respectively to fill the tank based on the given information.
1/x+2/x+4/x = 1/5
(1+2+4)/x = 1/5
7/x = 1/5
→ x = 7×5
→ x = 35 hours.
the time taken by pipe A alone to fill the tank is 35 hours.
Pipes B and C will take x/2 and x/4 hours respectively to fill the tank based on the given information.
1/x+2/x+4/x = 1/5
(1+2+4)/x = 1/5
7/x = 1/5
→ x = 7×5
→ x = 35 hours.
the time taken by pipe A alone to fill the tank is 35 hours.
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