Question

A tank is filled in 5 hours by three pipes. A, B and C. The pipe C is twice as fast as B and B is twice as fast as
A. How much time will pipe A alone take to fill the tank?
25 hrs
35 hrs
Cannot be determined
20 hrs
None of these
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Answer 1

Answer:

35 hrs

Step-by-step explanation:

Lets say pipe A feeds a gallon per hour, thus pipe B that's twice as fast feeds twice as much or 2 gallons per hour, then pipe C that's twice as fast as B would feed 4 gallons per hour that gives us a result of 7 gallons per hour in total for all three pipes multiply that for 5 hours and the result is 35 gallons, since you will attempt to fill up the tank with only pipe A and pipe A feeds only 1 gallon per hour it will take 35 hours to fill up a 35 gallon tank.