Question

A tank is filled in 7 hours by three pipes A, B and C. Pipe C is twice as fast as B and B is twice as fast as A. How much time will pipe A alone take to fill the tank?

Answer 1

Step-by-step

Answer = 49 hour.

Answer 2

Answer:

Pipe A alone can fill the whole tank in $49 \mathrm{hrs} .$

Step-by-step explanation:

Given:

A tank is filled in 7 hours by three pipes A, B and C. Pipe C is twice as fast as B and B is twice as fast as A.

To find:

Time will pipe A alone take to fill the tank

Solution:

Let the efficiency of pipe $A$ be 1 unit.

Efficiency of pipe $B=2$units

Efficiency of $C=4$ units

Total work $=(1+4+2) \times 7=49 units$

Pipe A alone can fill the whole tank in $=\frac{49}{1} =49 \mathrm{hrs} .$