Question

A tank is filled with two different liquids of relative densities rho 1 and rho 2. Area of the hole is negligible when it is compared with the area of cross section of the tank. Given rho 2/rho 1 = 3, H = 1.5 m and g = 10 m/s ^ 2 . Find the velocity of efflux in m/s ​

Answer 1

~$\small \blue {\sf{Answer }}$✨❤

Let the velocity at hole is v 1

Height is 2h

Therefore velocity is, v 1

= 2g 2h

Now pressure at hole 2 is

P= hρg+ 2h ×2ρg

Applying Bernoulli's theorem, P o

+2hρg=P o + 21

(2ρ)v 22

where P

o is the atmospheric pressure

Velocity at hole 2 is v 2

= 2g 2

3h = 3gh

Now, v 1

v 2 = gh

3gh

v 1 : v 2 = 3:1

$\huge \orange {\mathfrak{Thank You }}$