Math, asked by adityaraj0114, 2 months ago

A tank is fitted with two taps. The
first tap can fill tank competely
in 45 minutes and the second tap
can emp the full tank in one
hour. If both the taps are opened
alternately for one minute, then
in how many hours the empty
tank will be filled completely?​

Answers

Answered by choudharydakshya
0

Answer:

if both taps are opened alternatively for 1 minute tehn in 2 minutes 1 liter of tank will be filled. then 176 liters will be filled in 176 x 2=352 minutes. after the 352th minute tap A will open and fill the tank completely so tank will be completely filled in 353 minutes= 5 hours and 53 minutes.

Similar questions