A tank measures 20 cm by 15 cm by 15 cm. The tank is three-fourths full of water. A metal ball with diameter 6 cm is placed into the tank. If the spherical ball sinks to the bottom of the tank, then what is the amount by which the water level in the tank rises?
Answers
Given : A tank measures 20 cm by 15 cm by 15 cm.
The tank is three-fourths full of water.
A metal ball with diameter 6 cm is placed into the tank.
If the spherical ball sinks to the bottom of the tank,
To Find : the amount by which the water level in the tank rises?
Solution:
tank measures 20 cm by 15 cm by 15 cm.
Assuming Base = 15 by 15
And height 20 cm
Water level = (3/4)20 = 15 cm
A metal ball with diameter 6 cm
Radius = 3 cm
Volume of ball = (4/3)πr³
= (4/3)(22/7) 3³
= 113.14 cm³
Height raised = 113.14 / ( 15 * 15) = 0.503 cm
amount by which the water level in the tank rises = 0.503 cm
new level = 15.503 cm
Case 2 :
Assuming Base = 20 by 15
And height 15 cm
Water level = (3/4)15 = 11.25 cm
Volume of ball = 113.14 cm³
Height raised = 113.14 / ( 20 * 15) = 0.377 cm
amount by which the water level in the tank rises = 0.377 cm
new level =11.627 cm
Learn More:
A building is in the form of a hollow hemisphere of outer radius 100 ...
brainly.in/question/11750490
The diameters of the internal and external surfaces of a hollow ...
brainly.in/question/79845
Explanation:
Tank measures 20 cm by 15 cm by 15 cm.
Assuming Base = 15 by 15
And height 20 cm
Water level = (3/4)20 = 15 cm.
A metal ball with diameter 6 cm
Radius = 3 cm
Volume of ball = (4/3)Tr³
=(4/3)(22/7) 3³
= 113.14 cm³
Height raised = 113.14 / (15*15) = 0.503 cm
Amount by which the water level in the tank rises = 0.503 cm
new level = 15.503 cm
Case 2:
Assuming Base = 20 by 15
And height 15 cm
Water level = = (3/4)15
= 11.25 cm
Volume of ball = 113.14 cm³
Height raised = 113.14 / (20 * 15)
= 0.377 cm
Amount by which the water level in the tank rises = 0.377 cm
New level =11.627 cm.