Question

A tank of height of 50 m is filled with oil fully, if the bottom of the tank appears to be 40 m below its top, the refractive index of the oil should be​

Answer 1

$\huge\tt{\red{\underline{Given:}}}$

★The height of a tank is 50m is filled with oil.

★Apparent height of the tank is 40m

$\huge\tt{\red{\underline{To\:\:Find:}}}$

★Refractive index of the oil.

$\huge\tt{\red{\underline{Concept\:\:Used:}}}$

★We would use the formula related to finding apparent depth

$\huge\tt{\red{\underline{Answer:}}}$

We have,

The height of a tank = 50m .

Apparent height of the tank = 40m .

Now we know,

$\large\green{\boxed{h_{a}=\dfrac{h}{\mu}}}$

where

• h is real height
• $h_{a}$ is apparent height
• $\mu$ is the refractive index.

So,

$\implies \mu = \dfrac{h}{h_{a}}$

$\implies \mu =\dfrac{50m}{40m}$

$\implies \mu =\dfrac{\cancel{50m}^{\small{5}}}{\cancel{40m}^{\small{4}}}$

$\implies \mu =\dfrac{5}{4}$

${\underline{\boxed{.°. \mu= 1.25}}}$

Therefore the refractive index is 1.25.