a tank of size 10m ×10m×10m is full of water and built on the ground if g=10 m/s2,the potential energy of the water in the tank is?who answers for them 100 points.
Answers
Answered by
107
heya...!!!!
volume of tank = 10 × 10 × 10
=> 1000m³
we know that:-
mass = density × Volume
=> 10³m³ × 1000kg/m³
=> 10^6kg
now,
P.E = mgh
[ here height = 5m from the mid point of tank]
p.e = 10^6 × 10 × 5
=> 5 × 10^7 joule
volume of tank = 10 × 10 × 10
=> 1000m³
we know that:-
mass = density × Volume
=> 10³m³ × 1000kg/m³
=> 10^6kg
now,
P.E = mgh
[ here height = 5m from the mid point of tank]
p.e = 10^6 × 10 × 5
=> 5 × 10^7 joule
saiganeshu:
thanks
Answered by
73
Hi.
Here is your answer---
____________________
Given---
Dimensions of the Tank = 10 × 10 × 10
Volume of the Tank(Or Volume of the Water) = 1000 m³.
We know the Density of the Water = 1000 kg/m³.
Using the Relations,
Density = Mass/ Volume
1000 = Mass/1000
Mass = 10^6 Kg.
Since, The mass of the Body can be assumed at the center of mass which is at the Mid-point. Thus, height is also half of the Original Height, i.e. it is taken from the mid-point of the Tank.
Thus, Height(h) = 1/2 × 10
= 5 m.
For Potential Energy,
Using the Formula,
U = m × g × h.
= 10^6 × 10 × 5
= 5 × 10^7 J.
Thus, Potential Energy of the Water is 5 × 10^7 Joules.
_____________________
Hope it helps.
Have a nice day.
Here is your answer---
____________________
Given---
Dimensions of the Tank = 10 × 10 × 10
Volume of the Tank(Or Volume of the Water) = 1000 m³.
We know the Density of the Water = 1000 kg/m³.
Using the Relations,
Density = Mass/ Volume
1000 = Mass/1000
Mass = 10^6 Kg.
Since, The mass of the Body can be assumed at the center of mass which is at the Mid-point. Thus, height is also half of the Original Height, i.e. it is taken from the mid-point of the Tank.
Thus, Height(h) = 1/2 × 10
= 5 m.
For Potential Energy,
Using the Formula,
U = m × g × h.
= 10^6 × 10 × 5
= 5 × 10^7 J.
Thus, Potential Energy of the Water is 5 × 10^7 Joules.
_____________________
Hope it helps.
Have a nice day.
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