Question

A tank of square cross section 2m×2m is filled with water up to a height of 2.5 m . Find the thurst experience by a vertical and bottom of the tank​

Answer 1

Answer:

Explanation:

Thrust at the bottom surface

The pressure is uniformly distrubed over the bottom surface.

Thrust = Pressure × Area

=(2.5ρg)A=2.5×(1×103)[10(2×2)]

Thrust at the vertical surface:

On a vertical surface in contact with the liquid the pressure is not the same at all points. Points at greater depth experience the larger pressures and hence the greater thrust. Consider a vertical surface ABCD(l×h) in contact with the liquid of height h.

Divide the vertical surface ABCD into rectangular strips of height dx and area ldx. Then

F=∫PdA=∫A0(xρg)ldx=ρgh22

Expressing F as F=[h2ρg]=ρgh22

F= [Pressure at CG of vertical surface × [Area of surface]

=(2.52×ρ×g)(2×2.5)

=2.52×10−3×10×5=6.25×104