A tank of water is viewed normally from above. State how the depth of the tank appears to change. Draw a labelled ray diagram to justify your answer.
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i = apperent depth
d = actual depth
u = refractive index of incidence medium
v = –”– of refractive medium
vi = ud
so
i = ud/v
change in depth
= d - i
= d(1-u/v)
hope it helps you
@di
d = actual depth
u = refractive index of incidence medium
v = –”– of refractive medium
vi = ud
so
i = ud/v
change in depth
= d - i
= d(1-u/v)
hope it helps you
@di
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