Question

A tank whose length is 60 cm and breadth 30 cm contains water. A cubical steel box having edge of 30 cm is immersed completely in the tank. The water in the tank will rise by​

Answer 1

Answer:

60*30*30=540

Step-by-step explanation:

Answer 2

Given:

• Length , Breadth of a tank is 60 cm and 30 cm respectively .

• A cubical steel box having edge of 30 cm is immersed completely in the tank.

To Find:

• The water in the tank will rise by/Height .

Solution :

$\longmapsto \tt{length = 60 \: cm}$

$\longmapsto \tt{breadth = 30 \: cm}$

$\longmapsto \tt{side \: of \: cube \: (a) = 30 \: cm}$

Using Formula :

$\longmapsto \tt \boxed{volume \: of \: cuboid = volume \: of \: cube}$

Putting value :

$\longmapsto \tt{l \times{b} \times {h} = {a} ^{3} }$

$\longmapsto \tt{60 \times 30 \times {h} = 30 \times 30 \times 30}$

$\longmapsto \tt{h = \dfrac{{ \cancel{30}} \times {{ \cancel{30}}} \times {30}}{{ \cancel{60}} \times {{ \cancel{30}}}}}$

$\longmapsto \tt{h = \cancel \dfrac{30}{2}}$

$\longmapsto \tt \bf{h = 15 \: cm}$

So , The water will rise by 15 cm .

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