Question

A tank with length 10 m, breadth 8 m and depth 6 m is filled with water to the top. If g = 10 m/s2 and density of water is 1000 kg/m then the thrust on the bottom

Answer 1

Given A tank with length 10 m, breadth 8 m and depth 6 m is filled with water to the top. If g = 10 m/s2 and density of water is 1000 kg/m then the thrust on the bottom

We know that

        volume = length x breadth x height

                      =   10 m x 8 m x 6 m

       volume = 480 m³

   Thrust is given by density x V x g

                            = 1000 x 480 x 10

                           = 4800000 kg m/s²

                      Thrust = 4800000 N

Answer 2

length of the tank , L = 10m

breadth of the tank, B = 8m

depth of the tank , H = 6m

so, volume of the tank , V = L × B × H

= 10 × 8 × 6 = 480 m³

density of water , $\rho$ = 1000 kg/m³

Acceleration due to gravity, g = 10m/s²

now, thrust on the bottom , F = $V\rho g$

= 480m³ × 1000kg/m³ × 10m/s²

= 4,800,000 N

= 4.8 × 10^6 N

hence, thrust applied on the bottom of the tank by water = 4.8 × 10^6 N