Question

A tanker contains 983 litres of water. Due to leakage in the tanker, the quantity
of water decreases at the rate of 9 litres per hour. How much water will be left in
the tanker after 5 hours?

Answer 1

Amount of water reduced in 5 h = 5 x 9 = 45l
∴ Amount of water remaining = 983l - 45l = 938l

Answer 2

938- 983-(9×5)
=983-45
=938