Question

A tap can empty a tanj in one hour . A second can empty it in 30 minutes.If both the taps operate simultaneously, how much time is needed to empty the tank

Answer 1

Answer:

Step-by-step explanation:

Answer 2

The time needed to empty the tank by the two taps is 20 minutes.

If a tap can empty a tank in x minutes, then the rate of emptying the tank by the tap per minute is $\frac{1}{x}$

Also 1 hour = 60 minutes

So, rate of emptying the tank by the first tap per minute is  $\frac{1}{60}$. Similarly,

The rate of emptying the tank by the second tap per minute is $\frac{1}{30}$.

Thus, the rate of emptying the tank by the two taps are  $\frac{1}{60}$ and $\frac{1}{30}$ per minute respectively.

Rate of emptying the tank per minute,  when both operate simultaneously is given as :

$\frac{1}{60}$ + $\frac{1}{30}$ = $\frac{1+2}{60}$ = $\frac{3}{60}$ = $\frac{1}{20}$

∴So, the time taken by the two taps together to empty the tank = 20 minutes.