A tap can empty a tank in 45 minutes. A second tap can empty it in 30 minutes. If both the taps operate
simultaneously, how much time is needed to empty the tank?
(a) 18 min.
(b) 20 min.
(c) 40 min
(d) 45 min
Answers
Answered by
1
Answer:
18 min
Step-by-step explanation:
A tap can empty the tank in 45 minutes
In 1 minutes it can empty 1/45 part of the tank
Second tap , in 1 minutes it can empty 1/30 part of the tank
in 1 minutes both tap can empty
= 1/45 + 1/30 part
= (2+3)/90 part
=5/90 part
= 1/18 part.
Therefore, both tap take time to empty the full part of the tank = 18 minutes
Similar questions