Question

A tap can empty a tank in an hour and half and another tap can empty the same tank in half an hour. If both the taps operate simultaneously, then how much time (in minutes) is required to empty the tank?

Answer 1

This is the answer in photo so

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Answer 2

A can empty a pipe in 90 mins= 1/90

B can empty a pipe in 30 mins = 1/30

$\frac{1}{90} + \frac{1}{30} = \frac{4}{90}$

Time required to empty the tank = 90/4 = 22. 5 min

= 22 min 30 sec