Math, asked by punjabineel79, 5 months ago

A tap can fill a fan 8 hrs 2nd pipe can fill in 10 hrs . if both the pipes are work together, the will be filled in
(a) 18 hrs (b) 24 hrs (c) 36 hrs (d) 40 hrs
pls full explanation ​

Answers

Answered by ravinderjangra27
0

Answer:

in 18 hours. i hope my answer is correct

Step-by-step explanation:

=10 + 8

=18

Answered by ananya1368
2

Answer:

I guess the question is like this A tap can fill a tank in 8 hrs and 2nd pipe can empty it in 10 hrs.

Tap A fill tank in 8 hrs

Tap B empty tank in 10 hrs

Therefore, tank A's work in 1 hr =1/8

Tank B 's work in 1 hr= - 1/10 (tap B empties the tank)

Work done by (A+B) in 1 hour =

 \frac{1}{8}  -  \frac{1}{10}  =  \frac{5 - 4}{40}  =  \frac{1}{40}

Time taken by (A+B) to fill the tank =40hrs

Step-by-step explanation:

Hope it helps...

I tried to solve given question but it was not in the options...

If it is wrong pls forgive me...

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