Question

a tap can fill a tank in 4 hours and another tap can fill it in 6 hours if both the taps are opened how long will it take for the tank to be full​

Answer 1

Answer:

12/5 hrs or 2 hr 2/5 min

Step-by-step explanation:

part filled by tap A in 1 hr=1/4

part filled by tap B in 1 hr=1/6

both are opened s0

=1/4+1/6

=10/24

=5/12

take the reciprocal

so 12/5

so 2 hour (2/5) minutes

Answer 2

It will take $2\dfrac{2}{5}$ hours for both the tank to fill.

Step-by-step explanation:

Since we have given that

Time taken by first tap = 4 hours

Time taken by second tap = 6 hours

So, work done by both the taps would be

$\dfrac{1}{4}+\dfrac{1}{6}\\\\=\dfrac{3+2}{12}\\\\=\dfrac{5}{12}$

So, time taken by both would be

$\dfrac{12}{5}=2\dfrac{2}{5}\ hours$

Hence, it will take $2\dfrac{2}{5}$ hours for both the tank to fill.

# learn more:

A tap fills a tank in 2 hours and another tap can fill it in 6 hours. If both the taps are opened together, how long will it take to fill the tank?

https://brainly.in/question/3360742