Question

A tap can fill a tank is 25 minute and another tap can empty it in 50 minutes.If both one opened simultaneously when the tank be filled

Answer 1

work of first tap in 1 min =
$\frac{1}{25}$
work of second tap in 1 min =
$\frac{1}{50}$
work of both tap in 1 min =
$\frac{1}{25} + \frac{1}{50} = \frac{3}{50}$
so time it will take reverse the time it take in 1 min
$\frac{50}{3} min$

Answer 2

WORK OF FIRST TAP IN ONE MIN =1/25
WORK OF SECOND TAP IN ONE MIN =1/50
WORK DONE BY BOTH TAP IN ONE MIN =1/25+1/50=3/50
HENCE, TO FILL THE TANK FROM BOTH TAPS TAKE 50/3 MINS.
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