Question

A tap can fill a water tank in 10 hours. Due to leakage at the bottom, it is filled in 4 hours late. When the tank is full, in how much time will it get empty by the leakage?​

Answer 1

Answer:

35

Step-by-step explanation:

A tap can fill a tank in 10 hrs.

ie. In one hour tap can fill 1/10 th of tank

Due to leakage it filled 4 hr late. so it fill in 14hr.

with leakage in one hr tap can fill 1/14 th of tank

leakage can empty a tank in x hrs

in one hr leakage empty 1/x th of tank

$\frac{1}{10} - \frac{1}{x} = \frac{1}{14} \\ \\ \frac{1}{10} - \frac{1}{14} = \frac{1}{x}$

$\frac{1}{x} = \frac{ 1}{35}$

In one hr leakage empty 1/35 th of tank

Leakage can empty a tank in 35 hrs.