a tap can fill up the empty tank in 5 hours whereas it can be emptied by a pipe in 6 hours. how long will take to fill the empty tank if both the tap and pipe are opened together
Answers
Answered by
1
Answer:
In 1 HOUR Pipe A fills = 1/5 th part
In I hour pipe B empties = 1/6 th part
In 1 hour part of tank that can get filled if both taps are opened =( 1/5 -1/6 )th part = 1/30th part
So if 1/30 th part gets filled in =1 hour
1 whole part gets filled in = 1 ÷ ( 1/30 ) = 30 hours
Answered by
0
Step-by-step explanation:
Pipe A can billion empty tanks in 5hrs
⇒ billed by pipe A in hr =
5
1
Pipe B can fill an empty tank in 6hrs.
⇒ Part filled by pipe B in 1hr=
6
1
∴ tank filled by pipe AandB together in 1 hr =
5
1
−
6
1
=
30
1
∴ the tank can be filled in 30hrs.
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