Math, asked by abhishek0078640, 11 months ago

A tap fills 1/3 of a tank in 1 hour. Another tap empties 1/4 of tank in 1 hour. If both are open together then find the time when the tank will get filled completely.​

Answers

Answered by bikash717
3

Answer:

12 hours

Step-by-step explanation:

Let's say we have tank of 12 litres and name the tap as A and B

Tap A fills 1/3 of the tank means, it fills 4 litre per hour

Tap B empties 1/4 means it empties 3 litre per hour

if both opened together, 4+(-3) =1 litre is filled in one hour, so it requires 12 hours to fill the whole tank.


abhishek0078640: thanx
bikash717: no issue, you understand it na??
Answered by shahid78692
1

A tap fills 1/3 of a tank =1 hour

The same tap can fill a tank=1×3=3 hours.

Another tap fills 1/4 of a tank=1 hour

The same tap can fill a tank=1×4=4 hours.

If both tap are open and work done by both tap then=1/3+1/4=7/12

And time taken by two taps=12/7 hours...

I hope this answer will help you...


abhishek0078640: another tap doesn't fill the tank it empties the tank.
shahid78692: oh,no...
bikash717: thats y i have taken it negative and the resultant is 1 litre in 1 hour
shahid78692: i have mistaken... so sorry for this
bikash717: no issue
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