a tap is at 50 cm from ground and water droplets are falling in equal interval of time when 1st strikes at ground then at this time 4th drop leaves the tap then during this time height of 2nd and 3rd drop will be
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Height of tap = 5m and (g) = 10m/sec
2
For the first drop, 5=ut+gt
2
=(0×t)+×10t
2v
=5t
2
or t
2
=1 or t=1.
It mean that the third drop leaves after one second of the first drop. Or, each drop leaves after every 0.5 sec.
Distance covered by the second drop in 0.5 sec.
=(0.5)
2
=1.25m
Therefore, distance of the second drop above the ground
=5−1.25=3.75m
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