Question

A tap situated at the height of 10m leaks and the water drop falls at regular intervals. When the first drop reaches the ground, the 5th drop is about to leave the tap, then the separation between the second and the third drop is?

Answer 1

Velocity of drop 5m below the tap can be obtained by energy conservation.

Assume that potential energy is zero 5m below the tap.

Now, v=

2gh

=10m/s

Now, time taken to achieve this velocity=

10

10

=1s

it is given that drops leave the tap at a regular time interval. Thus, second drop will leave at 0.5s as the third drop is leaving at 1s.

Now, total time of motion of second drop is 0.5s

Thus, distance moved by second drop in 0.5s is

s=

2

1

×10×(0.5)

2

=1.25

Thus height from ground level is 5−1.25=3.75m