Math, asked by Gemsroy6706, 8 months ago

A target has a bull’s-eye with a diameter of 2 inches. The outer ring is 1 inch wide. What is the area of the outer ring? A circle has a radius of 2 feet. A larger circle is 1 foot larger than the smaller circle. 1 pi inches squared 3 pi inches squared 5 pi inches squared 12 pi inches squared

Answers

Answered by PRADEEPGURU
4

Answer:

3 pi inches²

Step-by-step explanation:

Inner radius =1 inch

Outer radius = 1 inch + 1 inch wide = 2 inch

Area of outer ring = pi x (outer radius)² -pi x( inner radius) ²

= pi x ( 2) ²-pi x (1)² = 4 pi - pi = 3 pi inches²

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