a taut string passes over a light smooth pulley at the end of a smooth table.It has mass 4 kg attached to one end and hanging freely, and a mass 2 kg attached to the end which lies on the table. Find the tension in the string and the accerlation of either mass.
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Answer:
Let the tension in the cord be T and the acceleration of the blocks be a.
Thus T=m
2
a
and m
1
g−T=m
1
a
⟹a=
m
1
+m
2
m
1
g
=
1+4
1
g=
5
g
=2m/s
2
Thus the velocity of block of mass m
1
=1kg when it reaches the bottom=
2as
=
2×2×1
m/s=2m/s
Explanation:
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Answered by
0
Answer:Let the tension in the cord be T and the acceleration of the blocks be a.
Thus T=m
2
a
and m
1
g−T=m
1
a
⟹a=
m
1
+m
2
m
1
g
=
1+4
1
g=
5
g
=2m/s
2
Thus the velocity of block of mass m
1
=1kg when it reaches the bottom=
2as
=
2×2×1
m/s=2m/s
Explanation:
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