Question

A taxi charges ₹50 for the first two km and ₹16 for the subsequent distance covered. Taking distance covered as x and total fare as y, write a linear equation in two variables. Find the fare for a distance of 16km

Answer 1

Answer:

324

Step-by-step explanation:

Fare of first two km is 50

Subsequent distance fare is 16

Total distance is x

Total fare is y

y=2*50+16(x-2)

y=100+16x-32

y=68+16x

Fare of 16 km

put the value of x=16

y=68+16*16

y=68+256

y=324

Answer 2

Answer:

y = 18 + 16x

374

Step-by-step explanation:

The taxi charge Rs 50  for the first two km.

and Rs 16 for the subsequent distances.

Taking the distance covered as x , and the fare as y,

we will get, the total fare as fixed Rs 50 for two km plus Rs 16 for more (x-2) km.

So , the equation can be written as y = $50 + (x-2) \times16$

$y = 16x +18$

Now we have to calculate  the fare for the distance of 16km.

∴ $y = 16 \times 16 + 18$

∴ y = Rs 374

So , the total fare will be Rs 374