Question

A taxi driver charges Rs. 10 for the first ten km and Rs. 5 for every km you travel thereafter. Form an equation in two variables showing the relation between total fare and distance traveled. If Tarang travels in all 50 km, then how much will he pay?

Answer 1

Answer:

10+5×40=10+200=210

10rs("10km")+5rs×40km

10+200=210

Answer 2

Answer:

Taxi fare for first kilometer = Rs. 10

Taxi fare for subsequent distance = Rs. 6

Total distance covered = x

Total fare = y

Since the fare for first kilometer = Rs. 10

According to problem,

Fare for (x - 1) kilometer = 6(x-1)

So, the total fare = 6(x-1) + 10

y = 6(x-1) + 10

y = 6x - 6 + 10

y = 6x + 4

Hence, y = 6x + 4 is the required linear equation.

Step-by-step explanation:

10+5×40=10+200=210

10rs("10km")+5rs×40km

10+200=210