A taxi driver takes some fixed charge and some amount for every KM travelled. Take x as fixed charge and y as fare per KM. Write the expression in linear form, if a person who has travelled 25 KM has to pay Rs. 100. Draw its graph also.i want a good answer as i have given you 50 points
Answers
Step-by-step explanation:
Let fixed charge be Rs x and charge per km be Rs y.
⇒x+10y=105...(1)
⇒x+15y=155..(2).
Now From eq 2
⇒15y=155−x
⇒y=
15
155−x
...(3)
Substituting y from eq3 in eq1
⇒x+
15
10(155−x)
=105
⇒15x+1550−10x=1575
⇒5x=1575−1550
⇒5x=25
⇒x=5
Substituting x in eq2
⇒5+15y=155
⇒15y=155−5
⇒15y=150
⇒y=10
Hence x=5 and y=10
Fixed charge is Rs.55 and the charge per kilometer is Rs.1010
For 2525 km person have to pay = 5+10×25=255Rs.
The taxi charges in a city consist of a fixed charge together with the charge for the distance covered. For a distance of 10 km, the charge paid is Rs. 105 and for a journey of 15 km, the charge paid is Rs. 155. What are the fixed charges and the charge per kilometer? How much does a person have to pay for traveling a distance of 25 km?
January 17, 2020
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Zaara Bisariya
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ANSWER
Let fixed charge be Rs x and charge per km be Rs y.
⇒x+10y=105...(1)
⇒x+15y=155..(2).
Now From eq 2
⇒15y=155−x
⇒y=
15
155−x
...(3)
Substituting y from eq3 in eq1
⇒x+
15
10(155−x)
=105
⇒15x+1550−10x=1575
⇒5x=1575−1550
⇒5x=25
⇒x=5
Substituting x in eq2
⇒5+15y=155
⇒15y=155−5
⇒15y=150
⇒y=10
Hence x=5 and y=10
Fixed charge is Rs.55 and the charge per kilometer is Rs.1010
For 2525 km person have to pay = 5+10×25=255Rs.