Question

A taxi fare in a city is as follows. For the first kilometer, the fare is Rs 8, for the subsequent distance it is Rs 5 per km.Taking the distance covered as x km and total fare as Rs y, write a linear equation for this information.

Answer 1

total fare of Rs y for covering distance of x km is given by
y = 8+5×(x-1)
or y= 8+5x-5 or, y = 5x +3

Answer 2

⇒ Let the total fare be = y Rs

⇒ Distance covered be = x km

⇒ For first subsequent distance (x - 1) km fare = 5(x - 1)

⇒ y = 8 + 5 (x - 1)

⇒ y = 8 + 5x - 5

⇒ y = 5x + 3

⇒ The coordinates of the following linear equation

1) x = 0, y = 3 (0,3)

2) x = 1, y = 8 (1,8)

3) x = 2, y = 13 (2,13)

4) x = 3, y = 18 (3,18)

APH