Question

A Taxi fare in a city is such that Rs. 50 is fixed amount and Rs. 16 is charged.Taking the distance covered as x km and total fare as Rs. y , Write the linear equation of x and y. I will mark you as the Brainliest answer if You are the first one.

Answer 1

Answer:

Given :-

• A Taxi fare in a city is such that Rs. 50 is fixed amount
• Rs. 16 is charged.
• Taking the distance covered as x km and total fare as Rs. y ,

To Find :-

• Write the linear equation of x and y

16x + 50 = y

x = 20km

So, Rs(16 × 20 + 50)

Rs (320 + 50) = ₹ 370

Hence He has to pay Rs 370 /- for 20km