Question

A taxi from rest accelerates uniformly over a time 5 seconds and covers a
distance of 10 m. Determine the accelerations of the taxi?​

Answer 1

Explanation:

Correct option is

B

8.10 m s

−2

using second eq of motion s=ut+1/2at

2

as u=0, a=

t

2

2s

=

5.21

2

2∗110

=8.10m/s

2

Answer 2

$\huge\bold{\mathtt{\red{A{\pink{N{\green{S{\blue{W{\purple{E{\orange{R}}}}}}}}}}}}}$

Step-by-step explanation:

=rest accelerates uniformly over a time 5 seconds

=distance of 10 m

speed=distance/time

therefore.

=10/5

=2

accelerations of the taxi is 2.

ᴵᴺᵀᴱᴿᴱˢᵀᴵᴺᴳ ᵟᵁᴱˢᵀᴵᴼᴺ