A taxi leaves the station X for station Y every 10 minutes. Simultaneously, a taxi leaves the station Y also for station X every 10 minutes. The taxis move at the same constant speed and go from X to Y or vice-versa in 2 hours. How many taxis coming from the other side will each taxi meet enroute from Y to X ?
Answers
Answered by
39
Answer:
There will be 11 taxis at a time in between stations coz after every 10 minutes lefts one .hence each taxi meets 22 taxis during too & fro . so including herself there will (11+11+1)23 taxis on the way to meet each other en-route .
Answered by
8
Answer:
The taxi will meet 12 other taxis.
Explanation:
- Let two taxi start at the same time from X & Y.
- As their speed is same, the taxi will not meet any one of the taxi starting from Y.
- So it can meet the taxis starting from X only.
- So in the two hours in which the taxi reaches X, 12 [2*60/10](time*time interval of starting of a taxi) taxis will start off.
- But due to same speed, it will meet the first taxi after 1 hour, second at 1 hour & 5min, third at 1 hour and 10 min, and so on.
- The last one(the 13th taxi) will meet it at X.
- So it will meet 12 taxis enroute from Y to X.
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