A taxi leaves the station X for station Y every 10 minutes. Simultaniously a taxi leaves the station Y also for station X every 10 minutes. The taxis move at the same constant speed and go from X to Y or vice versa in 2 hours. How many taxis coming from the other side will each taxi meet enroute from Y to X?
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23.
2(120/10) - 1 =23
At the end of 2 hours there will be 24 cars that would be meeting each other. Thus answer should be logically 24, but wherever this question is given (actually it's a popular question) we assume that 24th car is just leaving the 23rd car. So we don't consider it.
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2(120/10) - 1 =23
At the end of 2 hours there will be 24 cars that would be meeting each other. Thus answer should be logically 24, but wherever this question is given (actually it's a popular question) we assume that 24th car is just leaving the 23rd car. So we don't consider it.
MAKING U UNDERSTAND IT COMPLETELY IS NOT POSSIBLE IN THIS FORUM. I NEED TO TALK WITH U AND I HAVE TO SHOW U A DIAGRAM TOO.
U CAN MUGG THIS QUESTION. MY PHYSICS TEACHER TOLD ME THE SAME.
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