Question

A taxi was hired for a round trip from city A to city B it covered a distance of 500km in 7 hours anf returned in 6 hours find the average speed of the taxi got whole journey . find the average speed and average velocity for the whole journey?

Answer 1

Solution:-
From A to B he covered 500km
Then,again return from B to A and covered 500km.
so,
Total distance=500+500
$= > 1000km$
Total time=7+6
$= > 13hrs$
Since,
$average \: speed = \frac{total \: distance}{total \: time}$
$= > \frac{1000}{13} \\ = > 76.92$
Hence,average speed=76.92km/h

Now,
$averge \: velocity = \frac{displacement}{total \: time}$
As in this case he ruturn to his starting point means initial and final position are same.
So,displacement =0

$= > \frac{0}{13} \\ = > 0$

Hence,
Average velocity=0

Answer 2

Speed of the taxi in reaching the destination = 500/7 kmph
Speed of the taxi on returning to home = 500/6 kmph.

Average speed = v1 + v2 / 2 = 500/7 + 500/6 / 2 = 6(500 ) + 7(500) / 6(7)(2) = 3000 + 3500 / 84 = 6500/84 = 11 ( 500 ) / 4 ( 21 ) = 11(125)/21 = 1375/ 21 .

The taxi reaches the initial place again. So Displacement = 0

Average velocity = 0

Hope helped!