Math, asked by raziakhaleel19874, 3 months ago

A tea party is arranged for 18 people along two side of a long table with 9 chair on each side of four men with to sit on one practical side and three on the other side in how many ways can they seated​

Answers

Answered by BryanAguirre
0

Answer:

Step-by-step explanation:

There are 8 chair on each side of the table.  

Let the sides be represented by A and B.  

Let four persons sit on side A, then number of ways of arranging 4 persons on 8 chairs on side A=  

8

P  

4

​  

 

And two persons sit on side B.  

The number of ways of arranging 2 persons on 8 chairs on side B=  

8

P  

2

​  

 

The remaining 10 persons can be arranged in remaining 10 chairs in 10! ways.

Hence, the total number of ways in which the persons can be arranged is

8

P  

4

​  

×  

8

P  

2

​  

×10!=  

4!6!

8!8!10!

​  

 

Similar questions