A teacher challenges his class 7 students to try and 'invent' a divisibility test for 12. After discussing among themselves, the class comes up with 4 different answers, which are given below. Only one of them is correct. Which of these is a divisibility test for 12?
Answers
Answer
If a number is divisible by 3 and 4 both, then that number is divisible by 12.
Example=4416
Step-by-step explanation:
Step 1: To check divisibilty by 3
add all the digits e.g. 4+4+1+6=15
15 is divisible by 3
Hence 4416 is divisible by 3.
Step 2: To check divisibility by 4
Last 2 digit is 16
16 is divisible by 4
Hence 4416 is divisible by 4
Therefore 4416 is divisible by 12
- Divisibility for 12 :- The number should pa ss the divisibility tests for 3 and 4 .
Complete Question :- A teacher challenges his class 7 students to try and 'invent' a divisibility test for 12. After discussing among themselves, the class comes up with 4 different answers, which are given below. Only one of them is correct. Which of these is a divisibility test for 12 ?
A) The number should pa ss the divisibility tests for 2 and 6.
B) The number should pa ss the divisibility tests for 3 and 4.
C) The number should pa ss the divisibility tests for 2 and 10.
D) None of these - there is no divisibility test for 12.
Concept used :-
- Divisibility rule of 2 :- If unit digit of a number is 0,2,4,6 or 8 then, the number is divisible by 2 .
- Divisibility rule of 3 :- If sum of all digits of a number is divisible by 3, the given number is also divisible by 3 .
- Divisibility rule of 4 :- If last two digits { hundred place digit and unit place digit } are divisible by 4, the given number is also divisible by 4 .
- Divisibility rule of 6 :- If a number is divisible by 2 and 3 both, the given number is also divisible by 6 .
- Divisibility rule of 10 :- if unit digit of a number is equal to zero, the given number is divisible by 10 .
Solution :-
checking all 4 different answers given by students,
A) The number should pa ss the divisibility tests for 2 and 6.
Example :- 126
→ Unit digit = 6 , so given number is divisible by 2 .
also,
→ sum of number = 1 + 2 + 6 = 9 => 9 ÷ 3 = Remainder 0 . so given number is divisible by 3 .
since 126 is divisible by 2 and 3 both, it must be divisible by 6 also .
now, checking for 12 :-
→ 126 ÷ 12 = 10.5 or remainder is not equal to zero .
therefore, we can conclude that, if a number should pa ss the divisibility tests for 2 and 6, it may not pa ss the divisibility tests for 12 .
Hence, Answer (A) is incorrect .
B) The number should pa ss the divisibility tests for 3 and 4.
Example :- 792
checking if last two digits of the number are divisible by 4 :-
→ 792 ÷ 4 = 198 quotient and zero remainder .
So, 792 is divisible by 4 .
now,
→ sum of digit = 7 + 9 + 2 = 18 => Divisible by 3 { 6 × 3. }
So, 792 is divisible by 3 .
now, checking for 12 :-
→ 792 ÷ 12 = 66 quotient and zero remainder .
therefore, we can conclude that, if a number should pa ss the divisibility tests for 3 and 4, the given number is also divisible by 12 .
Hence, Answer (B) is correct .
C) The number should pa ss the divisibility tests for 2 and 10.
Example :- 200
Unit digit = 0, so given number is divisible by 2 and 10 both .
now, checking for 12 :-
→ 200 ÷ 12 = 16 quotient and 8 remainder .
since remainder is not equal to zero . Therefore, we can conclude that, if a number should pa ss the divisibility tests for 2 and 10, it may not pa ss the divisibility tests for 12 .
Hence, Answer (C) is incorrect .
∴ Answer (B) The number should pa ss the divisibility tests for 3 and 4 is correct answer .
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