Physics, asked by jaswanthdurgareddy, 6 hours ago

A teacher in a class room identified a student suffering with an eye defect

and observed his near point as 50cm.

Now answer the following questions.

i) What is his eye defect?

ii) Find the focal length of the lens used to correct his eye defect?​

Answers

Answered by uditchand446
1

Answer : (a) A student suffering from myopia is not able to see distinctly the objects placed beyond 5m. List two possible reasons due to which this defect of vision may have arisen. With the help of ray diagrams, explain

(i) why the student is unable to see distinctly the objects placed beyond 5m from his eyes.  

(ii) the type of the corrective lens used to restore proper vision and how this defect is corrected by the use of this lens.

(b) If, in this case, the numerical value of the focal length of the corrective lens is 5m, find the power of the lens as per the new Cartesian sign convention.

Answered by shwetal18
0

Answer:

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