A teacher pushed a 98 newton desk across a floor for a distance of 5 meters. He exerted a horizontal force of 20 newtons for four seconds.
a. How much work was
done?
b. What was his power?
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Answer:
a) the work done to move the across the floor is equal to
W = Fd
where is the horizontal force applied to move the desk on the floor and is the distance covered by desk
where
F= 20
d = 5
so according to formula
W= Fd = (20N) (5m)v
= 100 J
b)Power=Work/Time
Power=100/4=25
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