A Teacher wrote either of words "PARALLELOGRAM" and "PARALLELEPIPED" on board but due to malfunction of maker words is not properly written and only two consecutive letters "RA" are visible then the chance that the written word is "PARALLELOGRAM" is p/q then (p+q) equals. (where p & q are co prime natural numbers):
QGP:
The letters RA appear three times in all.
Answers
Answered by
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Hey There,
Here, we are given the letters RA, and also two words.
The words are:
PA RA LLELOG RA M
and
PA RA LLELEPIPED
Thus, we can see that the letters RA appear 3 times in all. Of them, they appear twice in Parallelogram.
So, the chances that the written word is Parallelogram is
Thus, we have:
Since 2 and 3 are co-prime numbers, we have:
p = 2, q = 3
So, p + q = 5
So, the answer is 5.
Hope it helps
Purva
Brainly Community
Here, we are given the letters RA, and also two words.
The words are:
PA RA LLELOG RA M
and
PA RA LLELEPIPED
Thus, we can see that the letters RA appear 3 times in all. Of them, they appear twice in Parallelogram.
So, the chances that the written word is Parallelogram is
Thus, we have:
Since 2 and 3 are co-prime numbers, we have:
p = 2, q = 3
So, p + q = 5
So, the answer is 5.
Hope it helps
Purva
Brainly Community
Answered by
0
RA twice in parallelogram and once in parallelepiped
p/q is 2/3
p+q is 2+3 is 5
so answer is 5
p/q is 2/3
p+q is 2+3 is 5
so answer is 5
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