Question

a team can do a particular task in 10 days.Another team cam do the same task in 20 days. In how many days the job be finished if the both teams work together​

Answer 1

Answer:

Total number of days taken by both the team to finish the work if they work together will be $=\frac{1}{\frac{3}{20}}=\frac{20}{3}=6\frac{2}{3}\:days$

Step-by-step explanation:

As per the data given in the question,

We have to determine the number of days taken by both team to complete the work if they work together.

As per the question,

It is given that,

A team can do a particular task in 10 days.

So, unit work or one day work of first team will be = (1/10) unit

As it is given that, another team can do the same task in 20 days.

So, unit work or one day work of second team will be = (1/20) unit

As both the team are working together.

So, unit work or one day work of both team (first team  and second team) will be $= (1/10)+(1/20) =\frac{2+1}{20}=\frac{3}{20}$

Let us assume that the,

Total work be = 1

So, total number of days taken by both the team to finish the work if they work together will be $=\frac{1}{\frac{3}{20}}=\frac{20}{3}=6\frac{2}{3}\:days$

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