Math, asked by rohitakole2004, 10 months ago

a team of 5 members is to be chosen from 7 men and 8 women it is decided that there can be at most 3 men in the team how many different ways are there to choose team

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Answered by saswatkumarsingh123
0

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Answered by ParvezShere
8

Given , Total number of members to selected in a team = 5

Number of men = 7 and the number of women = 8

It is given that the team can have atmost 3 men.

There are many cases in which the team can be formed.

Case 1 -

3 Men , 2 women

No. Of ways = 7C3 × 8C2 = 980

Case 2 -

2 Men , 3 Women

No. Of ways = 7C2 × 8C3 = 1176

Case 3 -

1 Man , 4 women

No. Of ways = 7C1 × 8C4 = 490

Case 4 -

5 Women

No. Of ways = 8C5 = 56

Total number of ways in which the team can be formed = 980 + 1176 + 490 + 56 = 2702

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