a team of 8 students goes on an excursion, in two cars, of which one can seat 5 and the other only 4. in how many ways can they travel?
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they can travel 5 -3 or 4-4 in 1st car to 2nd car respectively .
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Answer:
126 ways
Step-by-step explanation:
We can divide the students into two ways.
We have two cases:
Case I : 5 students in the first car and 3 students in the second car.
Case II : 4 students in the first car and 4 students in the second car.
We solve this using combinations.
In the first case we divide the 8 into : 8C3.
In the second case we divide the 8 into : 8C4
We have the solution as :
8C3 + 8C4 = 56 + 70 = 126
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