Question

a team use 2 dice for deciding the person who would give a talk on "technical aspects of effective communication".shalini will give a talk only if the product of two numbers that turn up is greater than 20.what is the probability that shalini would talk on the subject ​

Answer 1

Answer:

Answer is 1/6

Step-by-step explanation:

Possible combinations are

(4,6)

(5,5)

(5,6)

(6,4)

(6,5)

(6,6)

Then we favourable outcomes =6

And total outcomes =36

Probability =6/36

=>1/6

Answer 2

Given,

The team uses 2 dice for deciding who will speak.

Shalini will speak if the product of the numbers, when the dice are thrown = greater than 20.

To find,

The probability that Shalini will talk on the subject.

Solution,

Possible combinations,

= (1,1), (1,2), (1,3), (1,4), (1,5), (1,6),

  (2,1), (2,2), (2,3), (2,4), (2,5), (2,6),

  (3,1), (3,2), (3,3), (3,4), (3,5), (3,6),

  (4,1), (4,2), (4,3), (4,4), (4,5), (4,6),

  (5,1), (5,2), (5,3), (5,4), (5,5), (5,6),

  (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)

The possible combinations of obtaining a value greater than 20 when the dice are thrown = (4,6), (5,5), (5,6), (6,4), (6,5), (6,6)

Therefore,

Favourable number of outcomes = 6

Total number of outcomes = 36

Probability $=\frac{Favourable outcomes}{Total outcomes}$

                 $=\frac{6}{36}$

                 $=\frac{1}{6}$

Hence, the probability that Shalini would talk on the subject ​is $\frac{1}{6}$.