Question

a team won 6 hokey matches and lost 9 matchedls.What percent of matches did the team win​

Answer 1

Answer:

40 percent

Step-by-step explanation:

team won- 6

total no. of matches- 6+9=15

therefore,

$\frac{total \: no \: of match \: won}{total \: no \: of \: matches \: played}$

$\frac{6}{15} 100$

$\frac{6}{3} 20$

$2 \times 20$

$= 40\%$