A telephone pole is broken at a height of 10m from the ground and the top of the pole touches the ground at a distance of 25m from the base of the pole. How high was the telephone pole before it was broken?
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Answered by
1
Answer:
Let AB=10= Height of Pole
and AD be the length of the wire
From △ABD
sin45
o
=
AD
AB
⇒
2
1
=
AD
10
⇒AD=10
2
⇒10×1.414 (Take
2
=1.414)
=14.14 m
Answered by
1
Answer:
the length of the pole 36.952m
Step-by-step explanation:
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