Physics, asked by predators124, 1 year ago

a telephone wire 125m long and 1mm is radius is stretched to 9m length 125,25m long when force is acted in 800nm is applied what is the value of young modulus? ​

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Answered by Anonymous
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\huge\bold\green{Question}

A telephone wire 125m long and 1mm is radius is stretched to 9m length 125,25m long when force is acted in 800nm is applied what is the value of young modulus?

\huge\bold\green{Answer}

According to the question we have :-

→ Wire Length (l) = 125 m

→ Radius of wireb(r) = 1 mm

→ Streched Length of Wire (Δl) = 9 m

→ Given Force (f) = 800 nm

So, we have to find out the young modulus (y)

\begin{lgathered}\bold{So, \: lets \: start \: it} \\  = \text{Young \: Modulus} = \frac{ \text{force } \times \text\pink{Actual\:Length}}{ \text{Area }\times \text{ Change\:in\: Length}} \\ \\ \tt{Now  \:find \: cross \: section \: area} \\ = \text{Area} = \pi {r}^{2} \\ \\ = \text{Area} = 3.14 \times ({0.001})^{2} \\ \\ = \text{Area} = 3.14 \times 10^{ - 6} \\ \\ \text{By\: susituting \: given \: values} \\ = y = \frac{800 \times 125}{9 \times 3.14 \times 10^{ - 6} } \\ \\ = y = \frac{100000 \times 10^{6} }{28.26} \\ \\ \pink{ = \text{y = }3538.570417 \times 10^{6}N-m } \\ \\ \pink{ \text{Young \: Modulus   \:= }3538.570417 \times 10^{6} N-m}\end{lgathered}

Hence , the Young Modulus { y } of Wire is 3538.570417 × 10^6 N-m

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