Physics, asked by sidhuchowdary132, 2 months ago

A telescope consisting of an objective of focal length 60cm and a single eye lens of focal length 15cm is focused on a distant object in such a way that parallel rays comes out from the eye lens. If the object subtends an angle 2° at the objective, the angular width of the image.​

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Answered by diyakhrz12109
0

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eye lens of focal length 5 cm is focussed on a distant object in such a way that parallel rays comes out from the eye lens. If the object subtends an angle 2∘ at the objective, the angular width of the image

Magnification m=f0/fe

Also m=Angle subtanded by the imageAngle subtended by the object

∴f0/fe=α/β⇒α=f0×βfe

=60×25

=24∘

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