Question

A telescope consisting of an objective of focal length 60cm and a single eye lens of focal length 15cm is focused on a distant object in such a way that parallel rays comes out from the eye lens. If the object subtends an angle 2° at the objective, the angular width of the image.​

Answer 1

Explanation:

ANSWER

eye lens of focal length 5 cm is focussed on a distant object in such a way that parallel rays comes out from the eye lens. If the object subtends an angle 2∘ at the objective, the angular width of the image

Magnification m=f0/fe

Also m=Angle subtanded by the imageAngle subtended by the object

∴f0/fe=α/β⇒α=f0×βfe

=60×25

=24∘

Answer 2

Answer:

25°

Explanation:

M=αβ=fef0

∴β=fef0α=560×2o=24o=25°